Are these parallel, perpendicular, or neither? 2x-y= -1 and 4x-2y=6

Parallel

Step-by-step explanation:

Parallel lines have equal slopes

Perpendicular slope have a product = - 1

the equation of a line in slope-intercept form is

y = mx + c ( m is the slope and c the y-intercept )

rearrange both equations into this form and compare slopes

2x - y = - 1 ( subtract 2x from both sides )

- y = - 2x - 1 ( multiply through by - 1 )

y = 2x + 1 ← in slope-intercept form

with slope m = 2

4x - 2y = 6 ( subtract 4x from both sides )

- 2y = - 4x + 6 ( divide all terms by - 2 )

y = 2x - 3 ← in slope-intercept form

with slope m = 2

both equations have the same slope, therefore they are parallel

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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