Aperson goes to work across three intersections. the probability of seeing the red light at the first intersection is 60%, the probability of seeing the red light at the second intersection is 70%, and the third intersection is 80%. calculate the probability of the person walking without a red light

add together all (3) percentages                                                                        60+70+80=210subtract the answer from 300 (300 because there were 3 percentages)   300-210=90divide this answer by 3 (also because there were 3 percentages)            90/3=30the probability of the person walking without a red light is 30%