Bonus question solve 2a-b+c= -5 a - b+c= -5 by subsittution 2a + b =5 a. a= -2,b=0,c = -2 b. a= -2,b=0,c = -1 c. a= 1,b = 3,c= -6 d. a= 1,b = 3,c = -4

Please find the answer below

Step-by-step explanation:

2a-b+c= -5 (A)

a-b+c= -5 (B)

2a+b =5 (C)

from equation A subtracting 2a from both sides we get

-b+c = -5-2a

Substituting this value in B

a-5-2a=-5

a-2a-5+5=0

-a=0

a=0

Putting this value in C

2(0)+b=5

b=5

Putting these values in B

0-5+c=-5

c=0

We do not have any option with these solutions . Hence, it seems that there is something missing from the equation.

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step-by-step explanation:

geometry: triangles

solvers

lessons

answers archive

call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

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