50 ! if < pqr and < rqs form a linear pair, and, m< pqr = 5x + 5, and, m< rqs = 11x - 65, then: m< pqr = ?

If <PQR and <RQS form a linear pair, they are supplementary or add up to 180. So, (5x+5) + (11x-65) = 180 ... Combining like terms, it would be : 16x-60=180. 16x=240, x=15. They've asked for the measure of <PQR, so substitute it in! 5x+5= 5(15) +5= 80.

Happy Solving!

PQR = 80

Step-by-step explanation:

PQR and RQS make a line then their sum equals 180 degrees

5x+5 +11x-65 = 180

Combine like terms

16x -60 =180

Add 60 to each side

16x-60+60 = 180+60

16x = 240

Divide each side by 16

16x/16 = 240/16

x =15

We want to find PQR

PQR = 5x+5

         5(15) +5

         75+5

        80

answer: 25 is the correct answer

step-by-step explanation:

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option