Arectangular two-story horse barn is being designed for a farm. the upper floor will be used for storing hay, and the lower floor will have horse stalls that extend 6 feet from both of the longer walls. the barn's length is twice the barn's width, and the lower floor's ceiling height is 8 feet less than the barn's width. what should the dimensions of the lower floor be if the space not used for stalls is to have a volume of 3,840 cubic feet?

Let the width of the barn be = x feet

So length of the barn = 2x

Height of the barn = x-8

As the stalls are 6 feet longer from both ends hence, we have to find the area with width as x-12 feet

Volume of the space is = 3840 cubic feet

Hence, equation is :

Solving this we get

This gives x=20 and x= ±

Hence, neglecting the square root value we get x = 20 feet

Hence, the width is = x-12 = 20 - 12 = 8 feet

Length is = 2x = 2*20 = 40 feet

Height is = x-8 = 20 - 8 =12 feet

And we can cross check this by multiplying all the three dimensions to get 3840 cubic feet

cubic feet.

i believe

step-by-step explanation:

from my conclusion c

13

step-by-step explanation:

169-1=168

168-3=165

165-5=160

160-7=153

153-9=144

144-11=133

133-13=120

120-15=105

105-17=88

88-19=69

69-21=48

48-23=25

25-25=0

since it took 13times to completely subtract it hence its square root is 13