One morning, eight buses arrive at a bus stop. the number of minutes late for each bus is shown below. 0 8 2 6 9 2 0 7 8 in the afternoon, two more buses arrive at the bus stop. the median number of minutes late of all ten buses is 3.5. the mode number of minutes late of all ten buses is 0. how many minutes late were the two afternoon buses? urgent needed

0 and 5 minutes

step-by-step explanation:

given that one morning eight buses arrive late by the number of minutes given below:

0 8 2 6 9 2 0 7 8

write these in ascending order

0   0 2 6 7 8 8 9

in the afternoon two more buses arrive at the bus stop say by x and y minutes late.

total number of buses = 10

median = average of 4th and 5th after arranging in ascending order

since 4th entry is 6, the values of x and y should be below 6

also given 0 is the mode so either x or y or both should be 0 because then only 0 gets the maximum frequency and hence mode

thus we have

0 0 0 2 6 7 8 8 9 and another unknown entry which is below 6.

since median is 3.5, we have the unknown entry to be 5 only because then only median =( 2+5)/2

thus the after noon buses were late by 0 and 5 minutes.

the answer is d

the answer is in the first quadrant, which make the y-int positive.

since the dots are going down, therefore the correlation is negative

i hope it is right.

50*10 is greater

step-by-step explanation:

if you add the zero from 10 to 50, it will give you a bigger number.