Point b has coordinates ? (1? , the? x-coordinate of point a is negative 5. the distance between point a and point b is 10 units. what are the possible coordinates of point? a?

(- 5, - 6 ) or (- 5, 10 )

using the distance formula

d = √(x₂ - x₁ )² + (y₂ - y₁ )²

with (x₁, y₁ ) = (1, 2 ) and (x₂, y₂ ) = (- 5, y )

d = √(- 5 - 1 )² + (y - 2 )² = 10

d = √36 + (y - 2 )² = 10

square both sides

36 + (y - 2 )² = 100 ( subtract 36 from both sides )

(y - 2 )² = 64

take the square root of both sides

y - 2 = ± 8 ( add 2 to both sides )

y = 2 ± 8

y = 2 + 8 or y = 2 - 8 ⇒ y = 10 or y = - 6

coordinates of A = (- 5, - 6) or (- 5, 10 )

clock

step-by-step explanation:

step-by-step explanation:

given that ab is divided into equal parts as

ac, cd, de, ef, fg, gh, hi, ib.

from this we find that f is the midpoint of ab.

so using mid point formula we find

f = (3,7)

similarly considering fb, we get

h = mid point of fb = ((6,6) and g, mid point of fh is

g = (9/2, 13/2)

i is mid point of hb

so i =(15/2,11/2)