Mathematics
Mathematics, 01.07.2019 07:00, tre9990

βˆ’6 = 2/ 3 x nd a. = βˆ’9 b. = βˆ’6 c. = 4 d. = βˆ’4

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βˆ’6 = 2/ 3 x nd a. = βˆ’9 b. = βˆ’6 c. = 4 d. = βˆ’4...

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