The vertex of a parabola is at point 2,5.which equations could be for this parabola below? ? a.)y=(x-2)^2-5 b.)x=-4(y-2)^2 c.)y=(x+5)^2+2 d.)y=(x+2)^2-5

The vertex form of the equation of a vertical parabola is

y = (x-h)^2 + k, where (h,k) is the vertex.

Here, because the vertex is at (2,5), that equation must be:

y = (x-2)^2 + 5.

Answer A is closest, but ought to be A) y = (x-2)^2 + 5 (the 5 is positive).

answer:

c. the third graph

it is a secret for it not to be compromised sorry

step-by-step explanation: