What are the zeros of the quadratic function f(x) = 2x2 – 10x – 3? what are the solutions of this equation? 47 m 2 + 88 m + 39 = 0

Hi!

For f(x) = 2x^2 – 10x – 3, the zeros for this quadratic are:

For f(m) = 47m^2 – 88m + 33 = 0, the solutions for this equation are:

Step-by-step explanation:

Having a quadratic function: ax^2 + bx + c = 0, the values of x which are the solutions of the equation are given by the quadratic formula.

answer

d. 10

explanation

the distance from point y to wx is the height of the triangle.

using pythagoras theorem,

group similar terms to get,

this implies that,

take positive square root of both sides to get,

this implies that,

kaahe btau