Mathematics, 01.07.2019 09:30, kony345p
Write the equation in standard form for the circle that has a diameter with endpoints (0,8) and (0, - 8)
Answers: 2
![\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{0}~,~\stackrel{y_1}{8})\qquad (\stackrel{x_2}{0}~,~\stackrel{y_2}{-8})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ \stackrel{diameter}{d}=\sqrt{(0-0)^2+(-8-8)^2}\implies d=\sqrt{(-16)^2} \implies d=16 \\\\\\ \textit{so then the radius is half that }\cfrac{16}{2}\implies r=8 \\\\[-0.35em] \rule{34em}{0.25pt}](/tpl/images/0038/1811/bbc66.png)
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Write the equation in standard form for the circle that has a diameter with endpoints (0,8) and (0,...
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