Given f(x)=3x-1 and 9(x)=2x-3, for which value of x does g(x) =f(2)

f(2) is a constant, fill in x=2 for 3x-1 and find that f(2) = 5

So you have to solve g(x) = 5, ie., 2x-3 = 5

So add 3 to both sides and simplify:

2x -3+3 = 5+3

2x = 8

x = 4

. + λrh() e 1 1 2 4 4 4 4 4 3 4 4 4 4 4 + th−1(− s(x)2 dx ω + λrh−1() e 2 1 2 4 4

step-by-step explanation:

answer: b

step-by-step explanation: