Using one coordinate plane, graph the functions y=−4x+1 and y=2x−3, and find the coordinates of the point of intersection. now find the coordinates of the point of intersection without using the graphs. compare your two results.

f(x) = -4x + 1

g(x) = 2x - 3

Set each other equal and solve for x.

-4x + 1 = 2x - 3

-6x = -4

x = 2/3

substitute x into either f or g and solve for y

-4(2/3) + 1

y = -1.667...

Intersect at

(.667,-1.667)

In all honesty, there really is no “work” per say to show. mainly it’s just using the process of elimination. the question is asking which domain(s) would be the most appropriate for the function c(n). n is the number of observed vehicles so right away, 1, 2, and 3 can be eliminated.why? 1, 2 start in the negatives and therefore it is impossible to observe negative cars. so, #4 would be the best answer to the given problem.

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