Given the line 5x – 2y = 10, find the equation of a parallel line that passes through the point (2, 3). find the x- and y-intercepts of both lines. plot the intercepts and use them to graph both lines on the same set of axes.

1) for this problem you have to find the slope in first place of the  given line

5x-2y = 10 ⇒2y = 5x-10⇒y =(5/2)x-5

now to calculate the intersection points of the line 5x-2y = 10, you do x= 0 and obtain -2y= 10 therefore y = -5, the point of intersection with the axis y is (0,-5)

2) in second place ,if two lines are parallels then the slopes must be equal for both

m1 = 5/2

3) with the equation point- slope you can find the equation

y-y1 = m(x-x1)

y-3 = 5/2(x-2)⇒ 2y-6 = 5(x-2)⇒2y-6= 5x-10⇒5x-2y = 4

to find the intersection point with axis x and y , we procedure of similar form as the previous line

if x = 0 then y = -2 the point will be (0,-2)

if y = 0 then x = 4/5  the point will be ( 4/5,0)

90% rotation

step-by-step explanation:

answer are

step-by-step explanation: