In △abc point d is the midpoint of ab , point e is the midpoint of bc , and point f is the midpoint of be . find area of △abc, if adcf= 63 cm2.

For a better understanding of the solution given here please go through the diagram in the file attached. Let the area of the triangle ABC be denoted by the letter "a". We know that since D is the midpoint of AB then CD must be a median and we know that a median divides the area of any triangle in half. Thus, from the figure, Area of ….(Equation 1)Now, in  DE is the median and thus, Area of …(Equation 2)Again, in , DF is the median, so, area of …….(Equation 3)As, we can see, the area of the given triangle,  which is the sum of shaded areas depicted by "x" and "y". Now, this area is obviously, the sum of the area of (Equation 2) and (Equation 3). Thus we have: Solving, we get: sq. cm

10 * 563.67 = 5636.7

solution:

as, mean is defined as sum of all the observations divided by total number of observations.

and , median is mid value of the data whether arranged in ascending order or descending order.

consider, roadsters:

2,3,4,5,6,7,8,9

mean =

also, median= , because number of observations is even, so median is mean of two mid values.

now, coming to bandits

2,3,4,5,6

mean =  

median = 4, as number of observations is odd.

so, roadsters has greater median as well mean than bandits.

→option a is true about the repairs performed on 2 types of cars:

bandits have lower median and mean than roadsters.