Ihonestly just don't get this question. i'll give 30 !

sorry about your other question but here is the answer to this one

ok so her is what I think you do...

you have the equation y=3(x+1)^2+4 you use the distributive property to get rid of the prenticies so 3*x=3x and 3*1=3.  

Then you have y=3x^2+3^2+4 both of the numbers have a square root because the 2 beside the parinticies so both of those are squared

then u square what you can square so it would them be y=3x^2+9+4 because you can't square a variable and a number  it stays the same but because 3^2 can be squared is become 3*3 which equals 9

Then u combine the like terms you have making it y=3x^2+13 because of 9+4=14

then it says that y=x^2        so you put x^2=3x^2+13

after that you subtract -3x^2 from both sides making it -2x^2=13 because +x^2-3^2=-2x^2 and 3x^2-3x^2=0 so that goes away and you keep the +13

that is when you would divide by -2 on both sides making it -x^2=-13/2 which also equals -6.5(we will be using the decimal soon) because -2^2 divided by -2=-x^2 and 13 divided by -2 is -6.5

then u would find the square root of that by-{equation:\/(-x^2)=\/(-6.5)} -->\/(-x^2) which equals x because we don't know what x is it turns into jus x then as we move on =\/(-6.5)  which when you use a calculator it equals 2.54950976 but I would just round to the nearest hundreths making it 2.55 and that would be your answer

  b.   the average rate of change of f(x) is less than the average rate of change of g(x).

step-by-step explanation:

since the length of the interval is the same in each case, we only need to compare the change in y-value to see which is greater.

so the change in y-value for function f is (6 )) = 9.

the table tells us

so the change in y-value for function g is (31 -1) = 30.

the change in y-value of f(x) on the interval is less than the change in y-value of g(x) on the same interval, so the average rate of change of f(x) is less than the average rate of change of g(x).

nlgqer

step-by-step