The standard form of the equation of a parabola is x=y^2+10y+22 what is the vertex for of the equation

Complete the square of y^2 + 10y to answer this question.

x=y^2 + 10y + 22 becomes x = y^2 + 10y + 25 - 25 + 22,  or

x = (y+5)^2 - 3

Comparing this result to the generic form x = a(y-k)^2 + h, we see that

h = -5 and k = -3.

Then the vertex of this parabola is at (-5, -3).

this shows a reflection over the x-axis and is translated one unit down and 6 units to the right (x + 6, y - 1)

hope this !

~just a girl in love with shawn mendes