Which equation is quadratic in form? 2(x + 5)^2 + 8x + 5 + 6 = 0 x^6 + 6x^4 + 8 = 0 7x^6 + 36x^3 + 5 = 0 4x^9 + 20x^3 + 25 = 0

A quadratic equation refers to an equation with the highest degree of 2. The first equation, 2(x+5)^2 + 8x + 5 + 6 = 0 is the only one with the highest degree of 2 (in (x+5)^2), so that is the quadratic.

if the eqn of the parabola is f(x) = (x-4)(x+2), we need to mult. this out to find the coordinates of the vertex.

then f(x) = x^2 + 2x - 4x - 8, and f(x) = x^2 - 2x - 8.

one way in which you can find the vertex is to calculate x = -b / (2a).   here, that comes to

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x = = 1.   f(1) = 1^2 - 2(1) - 8 = - 9.   vertex is at (1, -9).

        2(1) 

find another point on the curve:   let x=0, for which y=-8.   then (0, -8) is on the curve.   plot the vertex and this point and draw a smooth parabola thru both.

hope this

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step-by-step explanation: