Nine less than nine times a number is at least thirty-six

let "a number" = x; at least = ≥

9x - 9 ≥ 36

Isolate the x. Do the opposite of PEMDAS.

First, add 9 to both sides

9x - 9 (+9) ≥ 36 (+9)

9x ≥ 45

Divide 9 from both sides to isolate the x.

(9x)/9 ≥ (45)/9

x ≥ 45/9

x ≥ 5

x ≥ 5 is your answer

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f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

i hope this you!

c.

step-by-step explanation:

she should of added 9^2 and 12^2. that is because it is a^2+b^2=c^2. c^2 is the hypotenuse and should always be bigger than the other two numbers. which is why she should of added 9 squared and 12 squared together instead of 15 squared.