What is the value for y? enter your answer in the box. y = an isosceles triangle a b c with horizontal base b c and vertex a is above the base. side a c and c b are labeled with single tick mark. all the three angles are labeled. base angles c a b is labeled as 50 degrees and angle c b a is labeled as 2x degrees. the angle a c b is labeled left parenthesis 5 y plus 10 right parenthesis degrees.

x = 25

y = 14

Explanation:

The described scenario can be represented using the attached triangle.

1- getting the value of x:

We know that ΔABC is an isosceles triangle with AC = BC

This means that:

∠CAB = ∠CBA

We know that ∠CAB = 50° and ∠CBA = 2x°

Equating the two angles, we get:

50 = 2x .................> Divide both sides by 2

x = 25

2- getting the value of y:

We know that the sum of the internal angles of a triangle is 180°

This means that:

∠ABC + ∠CAB + ∠ACB = 180°

We have:

∠ABC = 2x = 50°

∠ACB = 5y + 10

∠CAB = 50°

Now, we substitute to get the value of y as follows:

50 + 50 + 5y + 10 = 180

110 + 5y = 180

5y = 180 - 110

5y = 70 .............> Divide both sides by 5

y = 14

Hope this helps :)