Match each pair of points to the equation of the line that is parallel to the line passing through the points. b(5, 2) and c(7, -5) y = -0.5x − 3 d(11, 6) and e(5, 9) y = -3.5x − 15 f(-7, 12) and g(3, -8) y = 5x + 19 h(4, 4) and i(8, 9) y = 1.25x + 4 j(7, 2) and k(-9, 8) l(5, -7) and m(4, -12)

Since you only want to identify the parallel line, you only need to compute the slope between the two points. That is ...

... m = (y2 -y1)/(x2 -x1)

The line of interest will have this slope value as its x-coefficient.

BC: the slope is (-5-2)/(7-5) = -7/2 = -3.5 . . . . matches y = -3.5x -15

DE: the slope is (9-6)/(5-11) = 3/-6 = -0.5 . . . . matches y = -0.5x -3

FG: the slope is (-8-12)/(3-(-7)) = -20/10 = -2 . . . . no match

HI: the slope is (9-4)/(8-4) = 5/4 = 1.25 . . . . matches y = 1.25x +4

JK: the slope is (8-2)/(-9-7) = 6/-16 = -0.375 . . . .  no match

LM: the slope is (-12-(-7))/(4-5) = -5/-1 = 5 . . . . matches y = 5x +19

1. 3

2. 4

3. 1

hope this ! have a great day.

-wfz

is there any photos or whatever?