The vertex form of the equation of a parabola is y=(x+3)^2+53. what is the standard form?

"Standard form" appears like y = ax^2 + bx + c.

Starting with y=(x+3)^2+53, perform the indicated exponentiation / multiplication:

y = x^2 + 6x + 9 + 53.

Combining the constants, we get

y = x^2 + 6x + 62, which is the equation of a parabola in standard form.

y = x² + 6x + 62 ~apex I did it and it is correct

Step-by-step explanation:

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imma say 16%. sorry if its wrong. i'm doing the same stuff right now

step-by-step explanation: