Find two consecutive integers whose product is 30

consecutive integers can be represented as x an x+1

thei poduct is 30

so (x)(x+1)=30

use quadratic formula

for

for ours, a=1, b=1, c=-30

 or

x=(10/2) or x=-12/2

x=5 or x=-6

for x=5

x+1=6, the integers are 5 and 6

or x=-6

x+1=-5, the integers are -6 and -5

the integers are 5 and 6 or -5 and -6 (the question didn't say anything about the signs of the integers)

step-by-step explanation: the answer is 27. first multiply .32 by 25 which equals 8. then add 8 to 25 which gives you 33. then you subtract that from 6 since she gave 6 to her brother.

,, add !

the solution is x=1

step-by-step explanation:

we are given our   equation as

let's assume

left side function is

right side function is

now, we can draw graph

and then we can get intersection point

the intersection point will be solution

so, the solution is

x=1