Find the domain and range of f(x) = −x2 + 5

this is the answer, hope this helps

domain is the numbers you are allowed to use for the input, in this case x

range is the output you get from the domain after putting the domain into the function

to find the domain, I look at what number aren't allowed. some numbers that aren't allowed do stuf like make division by 0 or square root of a negative number

if we look at the function, no value of x with make a division by 0 or a square root of a negative number, so the domain is all real numbers

the range: we can see that this is a parabola that opens down, so it has a maximum but no minimum (goes down to negative infinity)

the max value of the parabola is the y value of the vertex

for ax^2+bx+c=f(x), the x value of the parabola is

or , a=-1 and b=0

subsituting that to find f(0) or the y value

f(0)=5

so the range is from negative ininity to 5

D={x | -∞<x<∞}

R={x | -∞<f(x)≤5}

im alright what do you need

step-by-step explanation:

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.