Find five consecutive odd integers such that the sum of the first and the fifth is one less than three times the fourth

STEP-BY-STEP SOLUTION:

Let number no. 1 ( smallest integer of the five integers ) = x

Therefore:

Number no. 4 = x + 6

Number no. 5 = x + 8

x + x + 8 = 3 ( x + 6 ) - 1

2x + 8 = 3x + 18 - 1

2x - 3x = 18 - 1 - 8

- x = 9

x = 9

Equations for each integer -

Number no. 1 = x = 9

Number no. 2 = x + 2 = 9 + 2 = 11

Number no. 3 = x + 4 = 9 + 4 = 13

Number no. 4 = x + 6 = 9 + 6 = 15

Number no. 5 = x + 8 = 9 + 8 = 17

FINAL ANSWER:

Therefore, the five consecutive odd integers are 9, 11, 13, 15 and 17.

Please mark as brainliest if you found this helpful! :)
Thank you and have a lovely day! <3