Two trains, train a and train b, simultaneously depart station a and station b. station a and station b are 252.5 miles apart from each other. train a is moving at 124.7mph towards station b, and train b is moving at 253.5mph towards station a. if both trains departed at 10: 00am and it is now 10: 08, how much longer until both trains pass each other?

-- The trains start moving at the same time.

-- The space between them is initially 252.5 miles.

-- They reduce the distance between them at the rate of (124.7+253.5)=378.2mph.

-- It will take them (252.5 / 378.2) = 0.6676 hour to meet.  

That's 40min 3.49sec .

-- After tooting and puffing toward each other for 8 minutes, they still have 32min 3.49sec to go before they meet each other.  We're all hoping that they're on different tracks.  

no, the equation would be invalid since they are both not equal.

step-by-step explanation:

here you got

4y-6+4y 2-9

first, you would simplify the equation on the form.

4y-6+4y 2-9

then, move all the terms that contains a y to the left and all the other terms to the right.

+4y-4y+-9-6

finally, you will simplify the left and the right side of the equation.

y=-3

give more details

step-by-step explanation: