Whlch set of numbers contains both solutions to the equation x2 - 2x - 8 = 0?

x = {-2, 4}

Step-by-step explanation:

0 = x² - 2x - 8

                    ∧

                 1    -8 = -7

                 2   -4  = -2  This works because the b-value is -2!

0 = (x + 2)(x - 4)

0 = x + 2       0 = x - 4

  x = -2              x = 4

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752