Three capacitors, a 12 mf, a 20 mf, and a 30 mf, are connected in series to a 60 hz source. the total xc is

Answer-

The total capacitive reactance of the circuit is 442.10 Ω.

Solution-

Three capacitors, a 12 mF, a 20 mF, and a 30 mF, are connected in series to a 60 Hz source.

The effective/equivalent capacitance of the circuit is,

When capacitors are joined in series, the total value of capacitance in the circuit is equal to the reciprocal of the sum of the reciprocals of capacitance of all the individual capacitors.

We know that,

Where,

= Capacitive Reactance (in Ω)

f = frequency (in Hz)

C = Capacitance (in F)

Here given,

= ??

f = 60 Hz

C = 6 mF = F

Putting the values in the formula,

Therefore, the total capacitive reactance of the circuit is 442.10 Ω.

sorry, i can't understand your question. will later if you describe more clearly!

: )

y = 3x+4

step-by-step explanation:

to find the slope

slope = (y2-y1)/ (x2-x1)

    = (-8-4)/ (-4-0)

    = -12/-4

  = 3

using the slope intercept form of a line

y= mx+b

we know the slope is 3

we know the y intercept is 4 ( the point where it crosses the y axis or x=0)

y = 3x+4