Two capacitors, a 20 mf and a 30 mf, are connected in parallel to a 400 hz source. the total capacitive reactance is

Answer-

The total capacitive reactance of the circuit is 7.96 Ω.

Solution-

Two capacitors, a 20 mF and a 30 mF, are connected in parallel to a 400 Hz source.

The effective/equivalent capacitance of the circuit is,

As, when capacitors are connected together in parallel, the equivalent capacitance in the circuit is equal to the sum of capacitance of all the individual capacitor.

We know that,

Where,

= Capacitive Reactance (in Ω)

f = frequency (in Hz)

C = Capacitance (in F)

Here given,

= ??

f = 400 Hz

C = 50 mF = F

Putting the values in the formula,

Therefore, the total capacitive reactance of the circuit is 7.96 Ω.

y=−9/2x+10

step-by-step explanation:

let's solve for y.

0−9x−2y=−20

step 1: add 9x to both sides.

−9x−2y+9x=−20+9x

−2y=9x−20

step 2: divide both sides by -2.

−2y

−2

=

9x−20

−2

y=

−9

2

x+10

answer: what in the world is this

step-by-step explanation: