The floor of a rectangular deck has a length that is 6 feet more than it’s width, x. hakeem is building the deck and decided to increase both dimensions by 3 feet. what is the new area, d, of the floor of the deck? a. x^2 + 12x + 27 b. x^2 + 9x + 18 c. x^2 + 9x d. x^2 +6x

Let the width of the rectangular deck be = x feet

The length is 6 feet more than the width so length is = x+6 feet

Let us assume that a total 3 feet is increased (1.5 feet on both ends)

As Hakeem decided to increase both dimensions by 3 feet, this means 1.5 feet is increased on both sides of the deck. So, length and width increases by 3 feet each.

Hence, new length is = x+6+3 = x+9 feet

New width is = x+3 feet

So new area = length*width

D =

=

= square feet

Hence, option A is correct.