Write an equation of the line that passes through (4,−1) and is parallel to the line y=3x+7. (hint: not y=3x-13)

To find the equation of the line, we are going to use the point-slope form, which is listed below:

You may notice that we have a point, but no slope is given to us. However, the problem states that the line is parallel to the equation , which means that it has the same slope as this line, which is 3. (Remember that this line is set up in form, where is the slope)

Thus, we can now insert our values into the point-slope formula to find the equation of our line.

The problem made it clear that it didn't want the form , so let's put it in standard form:

The equation of our line is .

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it