Aline passes through point (-2, 5) and has a slope of 2/3. points a(x, 3) and b(-2, y) lie on the line.
the value of x is the value of y is

Use the equation y = mx +c
y = 2/3x +c              Substitute the slope (m) in
5 = 2/3(-2) +c          Substitute the point (-2,5)
5 = -4/3 +c               Make C the subject
c = 19/3

y = 2/3x + 19/3        This is the equation of the line.

Next you start subbing the points A and B in separately, using the same equation.

Subbing A(x, 3)
3       = 2/3x + 19/3         Make x the subject to find it.
-10/3 = 2/3x
     -5 = x

The point A is (-5,3)

Subbing B(-2, y)
y = 2/3(-2) + 19/3           y is already the subject and you just solve it
   = -4/3 + 19/3
y = 5

The point B is (-2, 5)

I hope this helped you, I have also attached a photo of the written work! I'm also sorry if the answer isn't correct... >-<