What is the solution set of x^2 - 10 = 30x

x^2-30x-10=0

Use the quadratic formula

-b +or- square root of b^2 -4ac all divided by 2a

a = 1       b = -30      c = -10

30 +or- square root of (30)^2-4(-10) all divided by 2

(30+sqrt940)/2

x=30.33

(30-sqrt940)/2

x=-0.33

The solution is x=-0.33 and 30.33

x^2-30x-10=0

Use the quadratic formula

-b +or- square root of b^2 -4ac all divided by 2a

a = 1       b = -30      c = -10

30 +or- square root of (30)^2-4(-10) all divided by 2

(30+sqrt940)/2

x=30.33

(30-sqrt940)/2

x=-0.33

The solution is x=-0.33 and 30.33

7

step-by-step explanation:

the answer would be 7

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length