Write the equation of this line in slope-intercept form, when you give the answer, can you explain too. i am required to show my work.

For slope intercept form, you need to identify the slope and y-int of the graph.

y=mx+b, where m=the slope and b=the y-int

The y-int is (0,5), because it's at this point where the line crosses the y-axis. To find the slope, look at rise over run. Immediately you know that the slope is going to be negative because the line slopes down. The slope is -2/1, or just -2, because from one point to the other, the line goes down two points and to the right one point.

So, if m=-2 and b=5, you can set up the equation as y= -2x+5

differnt varibles efect the range

step-by-step explanation:

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.