Sketch the quadratic function f(x) = x2 + 4x + 3. which key feature of the graph is given incorrectly? a) minimum (-2, -1) b) y-intercept (0, 2) c) x-intercept (-3, 0) d) x-intercept (-1, 0) hurry if possible

Given quadratic function

Let us find vertex of the graph first.

x-coordinate of the vertex = -b/2a = -4/2(1) = -4/2 = -2.

y-coordinate of the vertex = (-2)^2+4(-2)+3 = 4-8+3 = -1.

Therefore, vertex is at (-2,-1).

The leading coefficient of quadratic function f(x)= x^2+4x+3 is 1.

And it's a positive number.

So, the parabola open up and it would have a minimum at it's vertex point.

Let us find some more points on the graph :

x=-3

(-3)^2 +4(-3) +3 = 9 -12 +3 =0

x=-1

(-1)^2 +4(-1) +3 = 1 -4 +3 = 0.

From the graph, we can see vertex is at (-2,-1) and x-intercepts at (-1,0), (-3,0) and y-intercept at (0,3).

Therefore, following is the key feature of the graph is given incorrectly:

answer:   28.56 feet (approx)

step-by-step explanation:

since, triangle abc has measure of angle c equal to 55 degrees, measure of angle abc equal to 90 degrees, and length of bc equal to 20 feet.

we have to find out the measurement of segment ab.

therefore, tan 55° =

but bc = 20 feet.

⇒ tan 55 ° =  

⇒ ab = 20 × tan 55 °

⇒ ab = 20 × 1.42814800674

⇒ ab = 28.5629601348   ≈ 28.56 feet

ƒ = 0.03b

hope this ( :

step-by-step explanation: