Line a is represented by the equation y=1/4x+8 how do these equations compare to line a? drag and drop the equations into the boxes to complete the table. parallel line a. perpendicular to line a. neither parallel nor perpendicular to line a y=1/4x+1. y=4x-8. y=-4x-3 a person out i'm totally clueless on this

Parallel line A :

Perpendicular to line A :

Neither parallel nor perpendicular to line A :

Step-by-step explanation:

The equation of line A is

      ... (1)

The slope intercept form of a line is

              .... (2)

where, m is slope and b is y-intercept.

From (1) and (2) we get

It means the slope of line A is 1/4.

The slope of parallel lines are same and the product of slopes of two perpendicular lines is -1.

In equation , the slope is 1/4 which is same as slope of line A. So, line is parallel to line A.

In equation , the slope is 4 which not equal to slope of line A and . So, line is neither parallel nor perpendicular to line A.

In equation , the slope is -4 which is not equal to the slope of line A and . So, line perpendicular to line A.

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2

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step-by-step explanation: