What is the vertex of the equation, y= -3x^2+2x-7? a. (1/3, -20/3) b. (-1/3, -20/3) c. (-1/3, -19/3) d. (1/3, -19/3)

A

Given a quadratic in standard form : y = ax² + bx + c ( a ≠ 0 ), then

The x-coordinate of the vertex is

= -

y = - 3x² + 2x - 7 is in standard form

with a = - 3, b = 2 and c = - 7, hence

= - =

Substitute this value into the equation for y-coordinate

y = - 3 ()² + 2 ( ) - 7

  = - + - = -

vertex = ( , - ) → A

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