Which values of ppp and qqq result in an equation with exactly one solution? -5x+12=px+q−5x+12=px+q choose all answers that apply: (choice a) a p=5p=5p, equals, 5 and q=12q=12q, equals, 12 (choice b) b p=-5p=−5p, equals, minus, 5 and q=-12q=−12q, equals, minus, 12 (choice c) c p=5p=5p, equals, 5 and q=-5q=−5q, equals, minus, 5 (choice d) d p=-12p=−12p, equals, minus, 12 and q=-12q=−12

We are given equation : -5x+12=Px+Q.

Let us compare left and right sides of the equation.

On comparing Px = -5x.

Dividing both sides by x, we get

Px/x = -5x/x.

P = -5.

Let us compare other part of the given equation.

Q =12.

Therefore, we got P=-5 and Q =12.

Non of the given options seems correct.

Please check the option have  P=-5 and Q =12.

Option A, C and D are correction Option.

Step-by-step explanation:

Given Equation, -5x + 12 = Px + Q

We have to value of P and Q from given options such that equation has exactly one solution.

First simplify the equation,

-5x + 12 = Px + Q

-5x - Px = Q - 12

(-5 - P)x = Q - 12

from above P can not have value equal to -5 as if P = -5

we have (-5 - (-5))x = Q - 12

               (-5 + 5)x = Q - 12

this equation has infinitely many solution as it removes x from the equation.

So, Option B is not our solution other than that All Options are our solution.

A).

P = 5 & Q = 12

⇒ (-5 - 5)x = 12 - 12

   x = 0

C).

P = 5 & Q = -5

⇒ (-5 - 5)x = -5 - 12

   -10x = -17

D).

P = -12 & Q = -12

⇒ (-5 - (-12))x = -12 - 12

   7x = -24

Therefore, Option A, C and D are correction Option.

c) yes, because of asa or aas

answer:

step-by-step explanation:

here, the total dishes = 10

dishes having meat = 3 ( chicken, meatloaf and hamburger )

thus, the probability of having meat on the chosen dishes = number of dishes having meat / total dishes

=

therefore, the probability of not having meat = 1- the probability of having meat on the chosen dishes

=

=

=

⇒ option b is correct.