Find three consecutive integers such that twice the greatest integer is two less than three times the least integer

we will take the least number as x and the largest as x+2 and the 2nd biggest as x+1

3x-2=x+2

3x=x+2+2

3x=x+4

3x-x=4

2x=4

x=2

x=2

x+1=3

x+2=4

we shall check whether it is right

just replace the x

3x-2=x+2

3*2-2=2+2

6-2=4

4=4

therefore the answer 2,3 and 4 is correct

you can't solve x because it is 2 linear equation and you only have one equation