Ineed with just the last question 3. a wildlife refuge in south america has howler monkeys and spider monkeys. a biologist working there randomly selected eight adults of each type of monkey, weighed them, and recorded their weights in pounds. howler monkey: {15, 16, 17, 17, 17, 17, 18, 19} spider monkey: {12, 13, 13, 14, 14, 14, 16, 16} (a) calculate the mean and mad for each type of monkey. (b) calculate the means-to-mad ratio for the two types of monkeys. (c) what inference can be made about the weight of both types of monkeys? explain. here's what i have so far: mad for howler monkey: 0.75 mad for the spider monkey: 14 means to mad ratio for the howler monkey and the spider monkey: 2.6249

Given:

howler monkey: {15, 16, 17, 17, 17, 17, 18, 19}

spider monkey: {12, 13, 13, 14, 14, 14, 16, 16}

The mean of the first set (howler monkey) = (15 + 16 + 17 + 17 + 17 +17 + 18 + 19)/ 8 

The sum of all weights is divided by the number of monkeys weighed (n = 8)

mean = 17

Do the same for the second set (spider monkey) = 12+ 13 + 13+ 14 + 14+ 14 +14 +16 + 16 / 8

mean = 15.75

the ratio of the two is 17:15.75 or 1.08 is to 1

the MAD for the howler monkey is 0.75

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

the least value out of the data shown is 5, maybe if you post a picture with it i could a little more.

step-by-step explanation: