Math ! which ordered pairs are solutions to the inequality

(1, -1), (5, -3)

Step-by-step explanation:

It is convenient to graph the solution space and plot the points.

You can also try the points in the inequality one by one (or all together).

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Here is the "all together" trial.

... {-3, 12, -2, -1, -3} - 2×{-6, 7, 0, 1, 5} ≤ -3 . . . . . use lists for x and y values

...  {-3, 12, -2, -1, -3} - {-12, 14, 0, 2, 10} ≤ -3 . . . . multiply the x list by 2

... {9, -2, -2, -3, -13} ≤ -3 . . . . . . . . . . . . . . . . . . . . perform the subtraction

The inequality is true for the last two values, corresponding to points ...

... (1, -1) and (5, -3)

hope it you

step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2