Did i calculate correctly? for exercises 3-6, solve the systems using the addition method. [question 4] 5a + 6b = -8 7a - 3b = 23 i chose to eliminate equation b. i multiplied the equation by two to eliminate b. 5a + 6b = -8 14a - 6b = 46 19a + 0 = 38 divide by 19 19a/19= a 38/19= 2 so [a] would equal 2. now i solve for b. 5(a)+6b= -8 10+6b= -8 -10 = -10 6b= -18 6b/6 = -18/6 b= -3 so [b] is equal to -3. my answer for question four is: (2, -3).