Use a graphing calculator to sketch the graph of the quadratic equation, and then state the domain and range. y=x^2+x+9 a. d: all real numbers r: (y ≤ 8.75) b. d: (x ≥ 0) r: (y ≥ 0) c. d: all real numbers r: (y ≥ 8.75) d. d: all real numbers r: (y ≥ -8.75)

Option c. D: all real numbers R: (y ≥ 8.75)

Solution:

y=x^2+x+9

Domain: all real numbers = ( - Infinite, Infinite)

y=ax^2+bx+c

a=1 > 0, the parabola opens upward: Range: y ≥k

b=1

c=9

Vertex: V=(h,k)

h=-b/(2a)

h=-1/(2(1))

h=-1/2

h=-0.5

k=y=h^2+h+9

k=(-0.5)^2+(-0.5)+9

k=0.25-0.5+9

k=8.75

Range: y≥k

Range: y≥8.75

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step-by-step explanation:

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check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.