What’s an equation of a line that’s perpendicular to 4x-16y=-8 and passes through the point (-3,3)

Let's first convert the equation of the line given to slope-intercept form:

We know that the slope (m in y = mx + b) is 1/4. A perpendicular line always has a negative reciprocal slope. So, the equation of the perpendicular line in slope-intercept form is simply:

But, since they give us two points on the line, we'll put that equation in point-slope form (y - k = m(x - h)):

So, your final answer is y - 3 = -4(x + 3).

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i