Given f'(x) = (x-4)(4-2x), find the x-coordinate for relative maximum on the graph of f(x)

The coordinate of the relative maximum is x=4.

Step-by-step explanation:

Given that the derivative of the function is , the maxima and minima or the critical points can be found where that is:

The solutions to this equation are and

Now, if the second derivative for a function  is negative at a critical point, then the critical point is the relative maximum.

Therefore we want to see at which of the two critical points is negative. The second derivative is:

Now is , and is , therefore we deduce that the relative maxium is located at , because there the second derivative is negative.

picture below

question

what is the value of the third quartile of the data set represented by this box plot? a. 19 b. 21 c. 26 d. 29

answer

c