Find the equation of the line that is perpendicular to the line y =- 1/3 x-1 and passes through the point (1, 5)? justify how you knew what slope to use for step 1. show all work needed to complete this problem

To find the other line's slope, take the "opposite reciprocal"

For example, if the slope is -1/3, you change the negative sign to positive and you take the reciprocal.

-1/3 --> +3/1

The slope of the perpendicular will be positive 3. To find the equation that passes through the point (1,5), substitute the x and y values into the equation y=mx+b and solve for b, because you know the slope already, now you have to find the y-intercept (the b in the equation).

5=3(1)+b

5=3+b

5-3= 3-3+b

2=b

The equation of the perpendicular line is y=3x+2

i used to know but i learned it a long time ago sorry

step-by-step explanation: