Use an addition property to solve for a. 10 + (–15) = –15 + a

Hi there!

a=10 and 10=a

Step-by-step explanation:

Addition property of equality is adding the same number to both sides of an equation does not change the equation.

switch sides.

-15+a=10-15

subtract by the numbers. subtract it's should be the found in the difference between the numbers, fractions, and spent.

10-15=-5

-15+a=-5

add 15 both sides of an equation.

-15+a+15=-5+15

simplify.

-5+15=10

15-5=10

10+5=15

15-5=10

a=10 and 10=a

Hope this helps!

-Charlie

Have a great day!

don't know what that says sorry i can't you

step-by-step explanation:

idk what it says

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.