What are the solutions of the equation x^6-9x^3+8= 0 use u substitution to solve

x = {1, 2}

Step-by-step explanation:

x⁶ - 9x³ + 8 = 0

Let u = x³  

⇒ (x³)² - 9(x³)¹ + 8(x³)⁰ = 0

⇒ u² - 9u + 8 = 0

⇒ (u - 1)(u - 8) = 0

⇒ u = 1 or u = 8

Replace u with x³

x³ = 1     or   x³ = 8

Take the cubed root of each side

x = 1     or     x = 2

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: