Maththe coordinates of the vertices of quadrilateral abcd are a(−4, −1) , b(−1, 2) , c(5, 1) , and d(1, −3) .

calculate the slopes of the lines using the gradient formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

(x₁, y₁ ) = A(- 4, - 1) and (x₂, y₂ ) = B(-1, 2 )

= = = 1

(x₁, y₁ ) = B(-1, 2) and (x₂, y₂ ) = (5, 1)

= = -

(x₁, y₁) = C(5, 1 ) and (x₂, y₂ ) = D(1, - 3)

= = = 1

(x₁, y₁) = A(- 4, - 1) and (x₂, y₂) = D(1, - 3 )

= = -

Quadrilateral ABCD is not a parallelogram since only one pair of opposite sides is parallel , that is AB and CD

i think the answer is seven, for if i'm being useless °ω°

step-by-step explanation:

answer: 0

step-by-step explanation: the positive, like 5, + its opposite, like -5 would be 0

5+(-5)=0, or 5-5=0