Identify the vertex, the axis of symmetry, the maximum or minimum value, and the range of the parabola. yequalsxsquaredplus2xplus1 the vertex is nothing. (type an ordered pair.)

Vertex = (-1, 0)

The axis of symmetry is x = -1

Minimum point is (-1, 0)

Range is y ≥ 0

In the interval notation [0, ∞)

Step-by-step explanation:

The given function is y = x^2 +2x + 1.

Write the given equation in the form of y = (x -h)^2 + k.

Here (h,k) is the vertex.

y = x^2 + 2x + 1

y = (x + 1)^2

Vertex = (-1, 0)

Axis of symmetry

The axis of symmetry splits the parabola in 2 equal parts.

In this equation, the axis of symmetry is x = -1

Maximum/minimum value

The parabola goes maximum when there is negative sign, it goes minimum when there is positive sign.

Here we have positive sign in front of (x + 1)^2, therefore, it is minimum at

y= 0

When y =0, x = -1

Therefore, minimum point is (-1, 0)

Range

Y- axis represents the range.

Here the minimum is 0, the maximum goes upto infinity.

Range is y ≥ 0

In the interval notation [0, ∞)

Herewith I have attached the graph of the function.

fist on the left goes with the third on the right. second on the left goes with the fourth on the right. third on the left goes with the second on the right. the fourth on the left goes with first on the right